The formula to calculate the Feed Water Enthalpy (H) is:
\[
H = \dot{m} \cdot h
\]
Where:
H – The feed water enthalpy in kilojoules (kJ).
\(\dot{m}\) – The mass flow rate of feed water in kilograms per second (kg/s).
h – The specific enthalpy of feed water in kilojoules per kilogram (kJ/kg).
Definition
Feed Water Enthalpy (H): The total energy content of the feed water used in various industrial processes.
Mass Flow Rate (\(\dot{m}\)): The amount of feed water flowing per unit time.
Specific Enthalpy (h): The energy content per unit mass of the feed water.
Example
Let's say the mass flow rate (\(\dot{m}\)) is 2 kg/s, and the specific enthalpy (h) is 500 kJ/kg. Using the formula:
\[
H = 2 \cdot 500 = 1000 \, \text{kJ}
\]
So, the feed water enthalpy is 1000 kJ.
Extended information about "Feed-Water-Enthalpy-Calculator"
Enthalpy of Feed Water
Definition: The enthalpy of feed water is the total heat content of the water used in a boiler system.
Formula: \( h = c_p \cdot T \)
\( h \): Enthalpy (kcal/kg)
\( c_p \): Specific heat capacity of water (kcal/kg°C)
\( T \): Temperature (°C)
Example: \( h = 1 \cdot 85 \)
\( h \): Enthalpy
\( c_p \): 1 kcal/kg°C
\( T \): 85°C
Specific Enthalpy of Water
Definition: The specific enthalpy of water is the enthalpy per unit mass of water.
Formula: \( h = u + p \cdot v \)
\( h \): Specific enthalpy (kJ/kg)
\( u \): Internal energy (kJ/kg)
\( p \): Pressure (kPa)
\( v \): Specific volume (m³/kg)
Example: \( h = 200 + 100 \cdot 0.001 \)
\( h \): Specific enthalpy
\( u \): 200 kJ/kg
\( p \): 100 kPa
\( v \): 0.001 m³/kg
Enthalpy of Hydration
Definition: The enthalpy of hydration is the heat change that occurs when one mole of an ion is dissolved in water to form an infinitely dilute solution.