To calculate the Reduction Potential (E):
\[ E = E^\circ - \left( \frac{RT}{nF} \right) \ln(Q) \]
Where:
Reduction potential, also known as redox potential or oxidation/reduction potential, is a measure of the tendency of a chemical species to acquire electrons and thereby be reduced. It is a critical concept in electrochemistry and is used to predict the direction of redox reactions. A higher reduction potential indicates a greater tendency to gain electrons and be reduced.
Let's assume the following values:
Step 1: Use the reduction potential calculation formula:
\[ E = 1.5 - \left( \frac{8.314 \times 298}{2 \times 96485} \right) \ln(0.1) \]
Step 2: Simplify the expression inside the parentheses:
\[ E = 1.5 - \left( \frac{2475.572}{192970} \right) \ln(0.1) \]
Step 3: Calculate the natural logarithm of 0.1:
\[ \ln(0.1) = -2.302585 \]
Step 4: Multiply and subtract:
\[ E = 1.5 - (0.01283 \times -2.302585) \approx 1.5 + 0.02956 = 1.53 \text{ V} \]
The Reduction Potential is approximately 1.53 V.