The formula to calculate the voltage from dBm is:
\[ V = \sqrt{(10^{\frac{dBm}{10}} \cdot 0.001 \cdot R)} \]
Where:
Let's say the power level (dBm) is 30 dBm and the resistance (R) is 50 Ohms. The voltage would be calculated as follows:
\[ V = \sqrt{(10^{\frac{30}{10}} \cdot 0.001 \cdot 50)} \approx 7.07 \text{ Volts} \]
So, the voltage is approximately 7.07 Volts.
dBm to Volts is a conversion process used in electrical engineering to change a measurement of power from decibels-milliwatts (dBm) to voltage (Volts). dBm is a unit of power that represents the ratio of a power level relative to a reference level of 1 milliwatt, expressed in decibels. The conversion is necessary because these two units measure different aspects of an electrical signal, and converting between them allows for more comprehensive analysis and understanding of the signal's behavior.
Formula: \( P_{\text{dBm}} = 10 \log_{10} \left( \frac{V^2}{R \times 1 \text{mW}} \right) \)
Example: \( P_{\text{dBm}} = 10 \log_{10} \left( \frac{2^2}{50 \times 1 \text{mW}} \right) \)
Formula: \( E = \sqrt{30 \times P_{\text{dBm}}} \)
Example: \( E = \sqrt{30 \times 10} \)
Formula: \( V = \sqrt{P_{\text{dBm}} \times R} \)
Example: \( V = \sqrt{10 \times 50} \)
Formula: \( V = 10^{\frac{dB}{20}} \times V_{\text{ref}} \)
Example: \( V = 10^{\frac{20}{20}} \times 1 \)
Formula: \( V = \sqrt{P_{\text{dBm}} \times R} \)
Example: \( V = \sqrt{5 \times 50} \)
Formula: \( P_{\text{dBm}} = 10 \log_{10} \left( \frac{V^2}{R \times 1 \text{mW}} \right) \)
Example: \( P_{\text{dBm}} = 10 \log_{10} \left( \frac{3^2}{50 \times 1 \text{mW}} \right) \)
