Magnetic Pull Force Calculator

Formula

To calculate the Magnetic Pull Force:

\[ F = \frac{\mu \cdot q1 \cdot q2}{4 \pi r^2} \]

Where:

\(F\) is the force between magnets (N)
\(\mu\) is the permeability of the medium between the magnets (T*m/A)
\(q1\) is the magnetic charge of the first magnet (A*m)
\(q2\) is the magnetic charge of the second magnet (A*m)
\(r\) is the distance between magnetic centers (m)

Magnetic Pull Force Definition

A magnetic pull force is the total force it takes to pull apart two opposing magnets due to the charge of their magnetic fields. This force is determined by the permeability of the medium between the magnets, the magnetic charges of the magnets, and the distance between their magnetic centers.

Example Calculation 1

Let's assume the following values:

Permeability of the Medium (\(\mu\)) = 1.25663706 × 10^-6 T*m/A
Magnetic Charge of the First Magnet (\(q1\)) = 2 A*m
Magnetic Charge of the Second Magnet (\(q2\)) = 3 A*m
Distance Between Magnetic Centers (\(r\)) = 0.5 m

Using the formula:

\[ F = \frac{1.25663706 \times 10^{-6} \cdot 2 \cdot 3}{4 \pi \cdot (0.5)^2} = 2.35 \times 10^{-6} \text{ N} \]

The Magnetic Pull Force is 2.35 × 10^-6 N.

Example Calculation 2

Let's assume the following values:

Permeability of the Medium (\(\mu\)) = 1.25663706 × 10^-6 T*m/A
Magnetic Charge of the First Magnet (\(q1\)) = 1 A*m
Magnetic Charge of the Second Magnet (\(q2\)) = 4 A*m
Distance Between Magnetic Centers (\(r\)) = 1 m

Using the formula:

\[ F = \frac{1.25663706 \times 10^{-6} \cdot 1 \cdot 4}{4 \pi \cdot (1)^2} = 4.00 \times 10^{-7} \text{ N} \]

The Magnetic Pull Force is 4.00 × 10^-7 N.