To calculate the Mass (\(M\)) from Energy (\(E\)):
\[ M = \frac{E}{c^2} \]
Where:
Impedance is the effective resistance of a circuit or component to an alternating current. This resistance arises from the effects of both ohmic resistance and reactance. In an ideal resistor, the resistance of the resistor is exactly equal to the impedance. In an ideal capacitor, the impedance is equal to the magnitude of the reactance. It should be noted that impedance is represented by an expression of a real and imaginary component, while reactance is an ordinary number. In the case of an ideal capacitor, however, we are assuming the imaginary part of this expression to be 0, and so we can represent the impedance using the formula above.
Let's assume the following values:
Using the formula:
\[ M = \frac{1,000,000}{(299,792,458)^2} = 1.11265 \times 10^{-11} \text{ kg} \]
The Mass is \(1.11265 \times 10^{-11}\) kg.
Let's assume the following values:
Using the formula:
\[ M = \frac{500,000}{(299,792,458)^2} = 5.56325 \times 10^{-12} \text{ kg} \]
The Mass is \(5.56325 \times 10^{-12}\) kg.
