The formula to calculate the departure angle (θ) is:
\[ \theta = \arctan\left(\frac{GC}{WB}\right) \times \frac{180}{\pi} \]
Where:
Let's say the ground clearance (\( GC \)) is 30 cm and the wheelbase (\( WB \)) is 150 cm. Using the formula:
\[ \theta = \arctan\left(\frac{30}{150}\right) \times \frac{180}{\pi} \]
We get:
\[ \theta = \arctan\left(0.2\right) \times \frac{180}{\pi} \]
\[ \theta \approx 11.31 \text{ degrees} \]
So, the departure angle (\( \theta \)) is approximately 11.31 degrees.
The departure angle is the maximum angle at which a vehicle can descend without any part of the rear of the vehicle hitting the ground. It is an important specification for off-road vehicles, as it determines the vehicle’s ability to navigate steep declines and obstacles without damage. The departure angle is influenced by the vehicle’s ground clearance and wheelbase, and a higher departure angle indicates better off-road capability.
Formula: \( \theta_d = \arctan \left( \frac{h}{l} \right) \)
Example: \( \theta_d = \arctan \left( \frac{0.5}{2.5} \right) \)
Formula: \( \theta_a = \arctan \left( \frac{h}{l} \right) \)
Example: \( \theta_a = \arctan \left( \frac{0.4}{2.0} \right) \)
Formula: \( D = L \cos(\theta) \)
Example: \( D = 50 \cos(30^\circ) \)
